Public Function GetFileName(ByVal FilePathFileName As String) As String '获取文件名 aaa.txt On Error Resume Next Dim i As Integer, J As Integer i = Len(FilePathFileName) J = InStrRev(FilePathFileName, "/") GetFileName = Mid(FilePathFileName, J + 1, i) End Function Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click MsgBox(GetFileName("/dir1001/aaa.txt")) End Sub |
转载请注明:vs2010» 获取路径下的文件名字
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